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Question

Question: The value of <sup>47</sup>C<sub>4</sub> + \(\sum_{r = 1}^{5}{(52 - r)C_{3}}\)...

The value of 47C4 + r=15(52r)C3\sum_{r = 1}^{5}{(52 - r)C_{3}}

A

53C353C_{3}

B

52C452C_{4}

C

52C552C_{5}

D

None

Answer

52C452C_{4}

Explanation

Solution

47C4 + r=15(52r)C3\sum_{r = 1}^{5}{(52 - r)C_{3}}

47C4+51C3+50C3+49C3+48C3+47C3\Rightarrow \underset{}{\overset{47C_{4} +^{51}C_{3} +^{50}C_{3} +^{49}C_{3} +^{48}C_{3} +^{47}C_{3}}{︸}}

48C448C_{4}

48C4+51C3+50C3+49C3+48C3\Rightarrow \underset{}{\overset{48C_{4} +^{51}C_{3} +^{50}C_{3} +^{49}C_{3} +^{48}C_{3}}{︸}}

49C449C_{4}

Similarly proceeding we get 52C4.