Question
Question: The value of <sup>47</sup>C<sub>4</sub> + \(\sum_{r = 1}^{5}{(52 - r)C_{3}}\)...
The value of 47C4 + ∑r=15(52−r)C3
A
53C3
B
52C4
C
52C5
D
None
Answer
52C4
Explanation
Solution
47C4 + ∑r=15(52−r)C3
⇒︸47C4+51C3+50C3+49C3+48C3+47C3
48C4
⇒︸48C4+51C3+50C3+49C3+48C3
49C4
Similarly proceeding we get 52C4.