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Question

Mathematics Question on Trigonometric Functions

The value of sin(45+θ)cos(45θ)sin\left(45^{\circ}+\theta\right)-cos\left(45^{\circ}-\theta\right) is

A

2cosθ2cos \theta

B

2sinθ2sin \theta

C

11

D

00

Answer

00

Explanation

Solution

sin(45+θ)cos(45θ)sin\left(45^{\circ}+\theta\right)-cos\left(45^{\circ}-\theta\right) =sin45cosθ+cos45sinθ=sin45^{\circ}\,cos\theta+cos45^{\circ}sin\theta [cos45cosθ+sin45sinθ]-\left[cos45^{\circ}\,cos\theta+sin45^{\circ}\,sin\theta\right] =12cosθ+12sinθ[12cosθ+12sinθ]=0=\frac{1}{\sqrt{2}}cos\,\theta+\frac{1}{\sqrt{2}}sin\,\theta-\left[\frac{1}{\sqrt{2}}cos\,\theta+\frac{1}{\sqrt{2}}sin\,\theta\right]=0