Question
Mathematics Question on Inverse Trigonometric Functions
The value of sin(2sin−10.8) is equal to
A
sin 1.2∘
B
0.96
C
0.48
D
sin 1.6∘
Answer
0.96
Explanation
Solution
Let E=sin(2sin−10.8)
Put sin−10.8=θ
⇒sinθ=0.8
∴cosθ=1−sin2θ
=1−0.64=0.36=0.6
∴E=sin(2θ)=2sinθcosθ
=2×0.8×0.6=0.96