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Question

Mathematics Question on Trigonometric Functions

The value of sin⁡251∘+sin⁡239∘\sin^2 51^\circ + \sin^2 39^\circ is

A

1

B

0

C

sin⁡12∘\sin 12^\circ

D

cos⁡12∘\cos 12^\circ

Answer

1

Explanation

Solution

sin⁡251∘+sin⁡239∘\sin ^{2} 51^{\circ}+\sin ^{2} 39^{\circ}
=cos⁡239∘+sin⁡239∘=\cos ^{2} 39^{\circ}+\sin ^{2} 39^{\circ}
=1=1