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Question

Mathematics Question on Matrices

The value of sec⁡[tan−1⁡(b+ab−a)−tan−1⁡(ab)]

A

(A) 2

B

(B) √2

C

(C) 4

D

(D) 1

Answer

(B) √2

Explanation

Solution

Explanation:
sec⁡[tan−1⁡(b+ab−a)−tan−1⁡(ab)]=sec⁡[tan−1⁡{b+ab−a−ab1+(b+ab−a)(ab)}]=sec⁡[tan−1⁡{1}]=sec⁡π4=2