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Question

Physics Question on Alternating current

The value of quality factor is

A

ωLR\frac{\omega L}{R}

B

1ωRC\frac{1}{\omega RC}

C

LC\sqrt{LC}

D

L/R.

Answer

1ωRC\frac{1}{\omega RC}

Explanation

Solution

Quality factor Q=ωLR\frac{\omega L}{R} Since ω2=1LC\omega^2=\frac{1}{LC} ∴ Quality factor Q=1ωRC\therefore \, Quality \, factor \, Q=\frac{1}{\omega RC}