Question

The value of net resistance of the network as shown in the given figure is :

• A. $\frac{5}{2} \, \Omega$
• B. $\frac{15}{4} \, \Omega$
• C. $6 \, \Omega$
• D. $\frac{30}{11} \, \Omega$

Answer 1

Answer: (C)

$6 \, \Omega$

Answer 2

The equivalent resistance is calculated as follows:

$R_{\text{eq}} = \frac{15 \times 10}{15 + 10} = \frac{150}{25} = 6 \, \Omega$

Diode 2 is in reverse bias, so no current will flow through the branch containing it. It can be treated as a broken wire.

Diode 1 is in forward bias and will behave as a conducting wire. The new circuit becomes a simpler parallel and series resistor network.