Question

The value of $\frac{\sqrt{x–2a} + \sqrt{x}–\sqrt{2a}}{\sqrt{x^{2}–4a^{2}}}$ is

• A. $\frac{1}{\sqrt{a}}$
• B. $\frac{1}{2\sqrt{a}}$
• C. $\frac{1}{3\sqrt{a}}$
• D. $\frac{1}{4\sqrt{a}}$

Answer 1

Answer: (B)

$\frac{1}{2\sqrt{a}}$

Answer 2

Apply L'H.Rule ⇒

= $\frac { ( \sqrt { x } + \sqrt { x - 2 a } ) } { \sqrt { x - 2 a } \sqrt { x } \cdot x }$.$\sqrt { x ^ { 2 } - 4 a ^ { 2 } }$= =