Question

The value of magnetic quantum number of the last electron of " $Na$ " is

• A. $3$
• B. $2$
• C. $1$
• D. $0$

Answer 1

Answer: (D)

$0$

Answer 2

Electronic configuration of $Na$ is $1s^{2}2s^{2}2p^{6}3s^{1}$ . Here the valence electron is in $3\,s$ orbital.
The $l$ value of this orbital is zero So, the magnetic quantum number of this orbital is zero