Question
Chemistry Question on Thermodynamics
The value of log10K for a reaction A ⇋ B is (Given ΔHº298K = –54.67 kJmol–1 ΔSº298K = 10 kJmol–1 and R = 8.314 JK–1mol–1 2.303 × 8.314 × 298 = 5705)
Answer
ΔGº = ΔHº – TΔSº = –54.07 × 1000 – 298 × 10 = –57050 ΔGº = –2.303 RTlog10K logK = 10