Question

The value of
$\lim\limits_{t→\infin}\left((\log(t^2+\frac{1}{t^2}))^{-1} \int\limits_{1}^{\pi t} \frac{\sin^25x}{x}dx\right)$
equals ___________ (rounded off to two decimal places).

Answer 1

The correct answer is 0.24 to 0.26. (approx)