Question
Mathematics Question on Some Properties of Definite Integrals
The value of (1+sin92π−icos92π1+sin92π+icos92π)3 is
A
−21(1−i3)
B
21(3+i)
C
−21(3−i)
D
21(1−i3)
Answer
−21(3−i)
Explanation
Solution
The correct answer is (C) : −21(3−i)
Let sin92π+icos92π=z
(1+zˉ1+z)3=(1+z11+z)3=z3
⇒(i(cos92π−isin92π))3
=−i(cos32π−isin32π)=−i(2−1−i2√ 3)
⇒2−1(√ 3−i).