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Question: The value of $\lambda$, for which the three lines $2x-5y+3=0, 5x-9y+\lambda=0$ and $x-2y+1=0$, are c...

The value of λ\lambda, for which the three lines 2x5y+3=0,5x9y+λ=02x-5y+3=0, 5x-9y+\lambda=0 and x2y+1=0x-2y+1=0, are concurrent, is

Answer

4

Explanation

Solution

Three lines are concurrent if they intersect at a single point. First, find the intersection point of the two lines that do not contain λ\lambda: 2x5y+3=02x-5y+3=0 and x2y+1=0x-2y+1=0. Solving these equations yields the point (1,1)(1,1). Substitute this point (1,1)(1,1) into the third line's equation, 5x9y+λ=05x-9y+\lambda=0, to find λ\lambda. This gives: 5(1)9(1)+λ=05(1) - 9(1) + \lambda = 0 59+λ=05 - 9 + \lambda = 0 4+λ=0-4 + \lambda = 0 Thus, λ=4\lambda=4.