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Question: The value of k for which the planes \(3 x - 6 y - 2 z = 7\) and \(2 x + y - k z = 5\) are perpendicu...

The value of k for which the planes 3x−6y−2z=73 x - 6 y - 2 z = 7 and 2x+y−kz=52 x + y - k z = 5 are perpendicular to each other, is

A

0

B

1

C

2

D

3

Answer

1

Explanation

Solution

Planes are perpendicular, if 6−6+2k=0⇒k=06 - 6 + 2 k = 0 \Rightarrow k = 0.