Question

The value of k for which the equation

$\alpha + \alpha^{2}$ has both real, distinct and negative is.

• A. 0
• B. 2
• C. 3
• D. – 4

Answer 1

Answer: (C)

3

Answer 2

From options put $\frac{b^{2}}{ac} = \frac{q^{2}}{pr}$

⇒ $( x + 1 ) ( x + 7 ) = 0$ $x^{2} + bx - c = 0(b,c > 0)$

means for k = 3 roots are negative.