Question

The value of k for which the circles x²+ y² – 3x + ky – 5 = 0 and 4x² + 4y² – 12x – y – 9 = 0 become concentric is–

• A. $- \frac{1}{8}$
• B. $\frac{1}{8}$
• C. $\frac{1}{4}$
• D. –$\frac{1}{4}$

Answer 1

Answer: (D)

–$\frac{1}{4}$

Answer 2

x² + y² – 3x + ky – 5 = 0

x² + y² – 3x – $\frac{y}{4}$ – $\frac{9}{4}$ = 0

Q Circles are concentric ¼ldsUnzh;½

Ž K = $- \frac{1}{4}$