QuestionReportMathematics Question on Definite IntegralThe value of ∫−11x2[x]dx\int\limits_{-1}^1x^2 [x] dx−1∫1x2[x]dx is:A13\frac{1}{3}31B23\frac{2}{3}32C1D−13-\frac{1}{3}−31Answer−13-\frac{1}{3}−31ExplanationSolutionThe correct option is(D):−13-\frac{1}{3}−31