Question

The value of $\int\limits_0^{4042}\frac{\sqrt{x}\ dx}{\sqrt{x}+\sqrt{4042-x}}$ is equal to

• A. 4042
• B. 2021
• C. 8084
• D. 1010

Answer 1

Answer: (B)

2021

Answer 2

The correct answer is (B) : 2021.