The value of (\integral\limits\_0^1\frac{\log(1+x)}{1+x^2}\... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The value of $\int\limits_0^1\frac{\log(1+x)}{1+x^2}\ dx$ is

A

$\frac{\pi}{2}\log2$

B

$\frac{\pi}{4}\log2$

C

$\frac{1}{2}$

D

$\frac{\pi}{8}\log2$

Answer

$\frac{\pi}{8}\log2$

Explanation

Solution

The correct answer is (D) : $\frac{\pi}{8}\log2$ .