Question
Mathematics Question on Calculus
The value of ∫−4π4π(x2sinx+x3)dx is:
A
21+64π4
B
21−64π4
C
0
D
64π4
Answer
0
Explanation
Solution
The correct option is (C): 0
The value of ∫−4π4π(x2sinx+x3)dx is:
21+64π4
21−64π4
0
64π4
0
The correct option is (C): 0