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Question

Mathematics Question on Definite Integral

The value of 1+x41+x6dx\int\frac{1+x^4}{1+x^6}dx is

A

tan-1 x + tan-1 x3 + C

B

tan-1 x + 13\frac{1}{3}tan-1 x3 + C

C

tan-1 x - 13\frac{1}{3}tan-1 x3 + C

D

tan-1 x + 13\frac{1}{3}tan-1 x2 + C

Answer

tan-1 x + 13\frac{1}{3}tan-1 x3 + C

Explanation

Solution

The correct answer is (B) : tan-1 x + 13\frac{1}{3}tan-1 x3 + C.