Question
Mathematics Question on Definite Integral
The value of ∫ex[1+cosx1+sinx]dx is equal to
A
extan2x+c
B
ex tanx +c
C
ex (1 + cosx) +c
D
ex (1 + sinx) +c
Answer
extan2x+c
Explanation
Solution
The correct answer is (A) : extan2x+c.
The value of ∫ex[1+cosx1+sinx]dx is equal to
extan2x+c
ex tanx +c
ex (1 + cosx) +c
ex (1 + sinx) +c
extan2x+c
The correct answer is (A) : extan2x+c.