The value of (\integral \_ { 1 } ^ { 2 } \log x d x) is | MATH - FUNDAMENTAL DEFINITE INTEGRATION, DEFINITE INTEGRATION BY SUBSTITUTION | SolveeIt

The value of $\int _ { 1 } ^ { 2 } \log x d x$ is

$\log 2 / e$

$\log 4$

$\log 4 / e$

$\log 2$

Answer

$\log 4 / e$

Explanation

$\int _ { 1 } ^ { 2 } \log x d x = [ x \log x - x ] _ { 1 } ^ { 2 } = 2 \log 2 - 2 + 1$

$= \log 4 - 1 = \log 4 - \log e = \log \frac { 4 } { e }$ .

Question: The value of \(\int _ { 1 } ^ { 2 } \log x d x\) is...