Question
Question: The value of \(\int _ { 0 } ^ { 1 } \left| 3 x ^ { 2 } - 1 \right| d x\) is...
The value of ∫013x2−1dx is
A
0
B
4/33
C
3/7
D
5/6
Answer
4/33
Explanation
Solution
∫013x2−1dx=∫01/3(1−3x2)dx+∫1/31(3x2−1)dx
=[x−x3]01/3+[x3−x]1/31
=31−331+33−1+31 =334.