QuestionReportMathematics Question on Definite IntegralThe value of ∫03∣2x−6∣dx\int_0^3 |2x-6|dx∫03∣2x−6∣dx is:A−94-\frac{9}{4}−49B192\frac{19}{2}219C9D-3Answer9ExplanationSolutionThe correct option is (C):9