Question
Question: The value of i log (x –i) + i<sup>2</sup>p + i<sup>3</sup> log (x + i) + i<sup>4</sup> (2 tan<sup>–...
The value of
i log (x –i) + i2p + i3 log (x + i) + i4 (2 tan–1x) where x > 0 and i = −1is
A
0
B
1
C
2
D
3
Answer
0
Explanation
Solution
I log x+ix−i– p + 2 tan–1 x = z (let)
\ log (x–ix+i) = i (z + p –2 tan–1 x)
or x–ix+i= eiq where q = z + p – 2 tan–1 x
x + i = x cos q + i x sin q + i sin q – i cos q
̃ x = cot 2θ ̃ q = 2 cot–1x
or z + p – 2 tan–1 x = 2 cot–1 x ̃ z = 0