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Question

Chemistry Question on trends in periodic table

The value of IE1,IE2,IE3,IE4I{{E}_{1}},\,I{{E}_{2}},\,I{{E}_{3}},\,I{{E}_{4}} and IE5I{{E}_{5}} of an element are 7.1, 14.3, 34.5, 46.8 and 162.2 eV respectively. The element is likely to be:

A

Na

B

Si

C

F

D

Ca

Answer

Si

Explanation

Solution

The values of ionisation energies shows that the element loose 4-electrons easily but not the fifth one. Hence, the element will be silicon, which has 4-electrons in its valence-shell to loose easily.