Solveeit Logo
Login

Question

Physics Question on the earth's magnetic field

The value of horizontal component of earths magnetic field at a place is 0.35×10−40.35\times10^{-4} tesla. If the angle of dip is 60060^0, the value of vertical component of earths magnetic field is about :

A

0.10×10−4 T0.10\times10^{-4}\,T

B

0.2×10−4 T0.2\times10^{-4}\,T

C

0.4×10−4 T0.4\times10^{-4}\,T

D

0.6×10−4 T0.6\times10^{-4}\,T

Answer

0.6×10−4 T0.6\times10^{-4}\,T

Explanation

Solution

By=BhB_y = B_h tan θ\theta = 0.35×10−4×0.35 \times 10^{-4} \times tan 60 = 0.60×10−10.60 \times 10^{-1} T.