Solveeit Logo
Login

Question

Chemistry Question on Solutions

The value of Henry?? law constant for some gases at 293 K293\, K is given below. Arrange the gases in the increasing order of their solubility. He:144.97 kbarHe : 144.97\, kbar, H2:69.16 kbarH_2 : 69.16\, kbar, N2:76.48 kbarN_2 : 76.48 \,kbar, O2:34.86 kbarO_2 : 34.86\, kbar

A

He<N2<H2<O2He < N_2 < H_2 < O_2

B

O2<H2<N2<HeO_2 < H_2 < N_2 < He

C

H2<N2<O2<HeH_2 < N_2 < O_2 < He

D

He<O2<N2<H2He < O_2 < N_2 < H_2

Answer

He<N2<H2<O2He < N_2 < H_2 < O_2

Explanation

Solution

KH=pxK _{ H }=\frac{ p }{ x } At constant pressure, KHK _{ H } is inversely proportional to xx. Therefore, the higher the KHK _{ H } lower the solubility. The increasing solubility order is: He<N2<H2<O2He < N _{2}< H _{2}< O _{2}