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Question

Physics Question on Gravitation

The value of g on earth's surface is 980 cms−2980\,cms^{-2}. The value at a height of 64 km from surface of earth is

A

960.4 cms−2960.4\, cm s^{-2}

B

984.9 cms−2984.9 \,cm s^{-2}

C

982.45 cms−2982.45 \,cm s^{-2}

D

977.55 cms−2977.55\, cm s^{-2}

Answer

960.4 cms−2960.4\, cm s^{-2}

Explanation

Solution

Using gh=gR2(R+h)2g_h = g \frac{R^2}{(R + h)^2}, we get gh=980(64006400+64)2g_h = 980 \left(\frac{6400}{6400 + 64} \right)^2 = 960 cm s−2s^{-2}