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Question

Physics Question on Gravitation

The value of g at a particular point is 9.8ms29.8 \, ms^{-2}. Suppose theearth suddenlyshrinks uniformly to half its present size without losing any mass. The value ofg at the same point (distance of the point from the centre of earth does not change) will now be

A

9.8ms29.8 \, ms^{-2}

B

4.9ms24.9 \, ms^{-2}

C

19.6ms219.6 \, ms^{-2}

D

39.2ms239.2 \, ms^{-2}

Answer

9.8ms29.8 \, ms^{-2}

Explanation

Solution

If gig_i be the initial value tor acceleration aue to gravity and gfg_f, be the final value then gi=GMR2=gg_{i}=\frac{G M}{R^{2}}=g and gf=GM(R2+R2)2=gg_{f}=\frac{G M}{\left(\frac{R}{2}+\frac{R}{2}\right)^{2}}=g