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Question

Physics Question on Gravitation

The value of gg at a height equal to half the radius of the earth from the earth's surface is

A

g2\frac{g}{2}

B

g3\frac{g}{3}

C

4g9\frac{4g}{9}

D

g4\frac{g}{4}

Answer

4g9\frac{4g}{9}

Explanation

Solution

Acceleration due to gravity at a height hh
from the earth's surface is gh=gRE2(RE+h)2g_{h} = \frac{gR^{2}_{E} }{\left(R_{E} +h\right)^{2}}
where g is acceleration due to gravity on the earth's surface.
At h=RE2,gh=gRE2(RE+RE2)2=49g h =\frac{R_{E}}{2} ,g_{h} = \frac{gR^{2}_{E}}{\left( R_{E} +\frac{R_{E}}{2}\right)^{2}} = \frac{4}{9}g