Question

The value of $\frac{5}{4} = - \frac{3}{4}A \Rightarrow$

• A. $\therefore$
• B. $- \frac{5}{3}\frac{1}{(2x - 1)} + \frac{1}{3}\frac{1}{(x + 1)} + \frac{1}{x - 1}$
• C. $ax - 1 = x(2 + x) - (1 - x + x^{2}) = 3x - 1$
• D. None of these

Answer 1

Answer: (B)

$- \frac{5}{3}\frac{1}{(2x - 1)} + \frac{1}{3}\frac{1}{(x + 1)} + \frac{1}{x - 1}$

Answer 2

$A = \log_{2}{\log_{2}{\log_{4}2}}56$

= $2{\log_{2}{}_{1/2}}2$= $= \log_{2}{\log_{2}{\log_{4}4^{4}}} + 2 \times \frac{1}{(1/2)}\log_{2}2$

= $= \log_{2}{\log_{2}4} + 4 = \log_{2}{\log_{2}2^{2}} + 4$.