The value of (= \frac{1}{x^{2} - x + 1} - \frac{1}{x^{2} + x... | MATH - INDICES AND SURDS | SolveeIt

The value of $= \frac{1}{x^{2} - x + 1} - \frac{1}{x^{2} + x + 1}$ is.

$\Rightarrow$

$a = 3,a + b = 5 \Rightarrow b = 2$

$\therefore$

$(a,b) = (3,2)$

Answer

$\therefore$

Explanation

$(1 + x)^{- 1} = \log_{abc}a$

$(1 + x)^{- 1} + (1 + y)^{- 1} + (1 + z)^{- 1} = \log_{abc}a + \log_{abc}b + \log_{abc}c$

Question: The value of \(= \frac{1}{x^{2} - x + 1} - \frac{1}{x^{2} + x + 1}\)is....