Question
Mathematics Question on integral
The value of π80∫2π(sinx)2023+(cosx)2023(cosx)2023dx is
Answer
The correct answer is 2.
I=π80∫2π(sinx)2023+(cosx)2023(cosx)2023dx......(1)
Using 0∫af(x)dx=0∫af(a−x)dx
I=π80∫2π(sinx)2023+(cosx)2023(sinx)2023dx........(2)
Adding (1) & (2)
2I=π80∫2π1dx
I=2