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Question

Mathematics Question on Simplification

The value of 1×22+2×32+...+100×(101)212×2×22×3+...+1002×101\frac{1\times 2^2+2\times3^2+...+100\times (101)^2}{1^2 \times 2\times2^2 \times3+...+100^2 \times 101}

A

305/301

B

301/305

C

350/310

D

310/350

Answer

305/301

Explanation

Solution

The Correct answer is option(A) : 305/301