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Question

Mathematics Question on Trigonometric Equations

The value of 1+tan2θ1+cot2θ×(1sin2θ)\frac {1+tan^2θ}{1+cot^2θ} \times (1-sin^2θ) is

A

1sec2θ\frac {1}{sec^2θ}

B

1cosec2θ\frac {1}{cosec^2θ}

C

tan2θtan^2θ

D

cot2θcot^2θ

Answer

1cosec2θ\frac {1}{cosec^2θ}

Explanation

Solution

The correct option is (B): 1cosec2θ\frac {1}{cosec^2θ}.