The value of (\frac{1}{log\_2N}+\frac{1}{log\_3N}+\frac{1}{l... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The value of $\frac{1}{log_2N}+\frac{1}{log_3N}+\frac{1}{log_4N}+....\frac{1}{log_15N}$ is

A

$\frac{1}{log_15^2N}$

B

$log_N(15!)^2$

C

$\frac{1}{log_N}(15!)$

D

$log_N(15)^2$

Answer

$\frac{1}{log_15^2N}$

Explanation

Solution

The correct option is(A): $\frac{1}{log_15^2N}$