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Question: The value of \(f^{- 1}(y) = \frac{x + 4}{3}\)so that the function, \(2 + x^{2}\) becomes continuou...

The value of f1(y)=x+43f^{- 1}(y) = \frac{x + 4}{3}so that the function,

2+x22 + x^{2} becomes

continuous for all x, is given by

A

1+x1 + x

B

2+x2 + x

C

f:RRf:R \rightarrow R

D

f(x)=x[x],f(x) = x - \lbrack x\rbrack,

Answer

f:RRf:R \rightarrow R

Explanation

Solution

ff is continuous for all xx except possibly at x = 0. In order that f becomes continuous at x =0, we must have f(0)=limx0f(x)f ( 0 ) = \lim _ { x \rightarrow 0 } f ( x )

=limx0a2ax+x2a2+ax+x2a+xax\lim _ { x \rightarrow 0 } \frac { \sqrt { a ^ { 2 } - a x + x ^ { 2 } } - \sqrt { a ^ { 2 } + a x + x ^ { 2 } } } { \sqrt { a + x } - \sqrt { a - x } }

=

=