Question
Question: The value of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ion...
The value of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is:
A
43%
B
50%
C
55.3%
D
72.24%
Answer
72.24%
Explanation
Solution
DEN = 4.0 – 1.2
= 2.8
% Ionic Character = 16DEN + 3.5 (DEN)2
= 16 × 2.8 + 3.5 (2.8)2 = 72.24 %