Chemistry Question on Classification of elements & periodicity in properties

Question

The value of electronegativity of /atoms $A$ and $B$ are $1.2$ and $4.0$ respectively. The $\%$ ionic character of the $A - B$ bond is

Answer 1

Solution

$X_{A}=1.2, X_{B}=4.0$
$\%$ ionic character $=16\left[X_{A}-X_{B}\right]+3.5\left(X_{A}-X_{B}\right)^{2}$
$=16(1.2-4.0)+3.5(1.2-4.0)^{2}$
$=44.8+27.44$
$=72.24 \%$