Question
Mathematics Question on Sequence and series
The value of k=1∑10 (sin112kπ+icos112kπ) is :
A
1
B
−1
C
−i
D
i
Answer
−i
Explanation
Solution
k=1∑10 (sin112kπ+icos112kπ) i=k=1∑10 (cos112kπ+isin112kπ) =ik=1∑10 (e−112kπ) =i\left\\{\displaystyle \sum_{k=0}^{10}\left(e^{-} \frac{2k\pi}{11}\right)-1\right\\}