Question

The value of $\displaystyle\lim_{n\to\infty}\left(\frac{1}{n+1} +\frac{1}{n+2}+... +\frac{1}{6n}\right)$ is

• A. $\log\, 2$
• B. $\log\, 6$
• C. $1$
• D. $\log\, 3$

Answer 1

Answer: (B)

$\log\, 6$

Answer 2

We know that,