The value of (\displaystyle\integral^{\frac{\pi}{2}}\_{\frac... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The value of $\displaystyle\int^{\frac{\pi}{2}}_{\frac{\pi}{6}}\frac{\cot x}{\sin x}dx$ is equal to

A

$\frac{-1}{2}$

B

$\frac{\1}{2}$

C

$\frac{-3}{2}$

D

$\frac{3}{2}$

E

1

Answer

1

Explanation

Solution

The correct option is (E) : 1