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Question

Mathematics Question on Integration

The value of ∫0π16cos⁡6xcos⁡2xdx\displaystyle\int^{\frac{\pi}{16}}_{0}\cos6x\cos2xdx is equal to

A

1+216\frac{1+\sqrt 2}{16}

B

1+28\frac{1+\sqrt 2}{8}

C

2+216\frac{2+\sqrt 2}{16}

D

−1+216\frac{-1+\sqrt 2}{16}

E

−1+28\frac{-1+\sqrt 2}{8}

Answer

1+216\frac{1+\sqrt 2}{16}

Explanation

Solution

The correct option is (A) : 1+216\frac{1+\sqrt 2}{16}