The value of (\displaystyle\integral\_{0}^{\sqrt3}\frac{6}{9... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The value of $\displaystyle\int_{0}^{\sqrt3}\frac{6}{9+x^2}dx$ is equal to

A

$\frac{\pi}{3}$

B

$\frac{\pi}{6}$

C

$\frac{\pi}{4}$

D

$\frac{2\pi}{3}$

E

1

Answer

$\frac{\pi}{3}$

Explanation

Solution

The correct option is (A): $\frac{\pi}{3}$