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Question

Chemistry Question on Enthalpy change

The value of (ΔHΔE\Delta H - \Delta E) for the reaction C6H6(1)+712O2(g)6CO2(g)+3H2O(I)C_6H_6(1) + 7\frac{1}{2} O_2(g) \rightarrow 6CO_2(g) + 3H_2O(I) at 270C is (R = 2 cal K-1 mol-1)

A

0.9 kcal

B

9 kcal

C

-0.9 kcal

D

-9 kcal

Answer

-0.9 kcal

Explanation

Solution

Answer (c) -0.9 kcal