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Question

Question: The value of D= \(\left| \begin{matrix} a & a + b & a + 2b \\ a + 2b & a & a + b \\ a + b & a + 2b ...

The value of

D= aa+ba+2ba+2baa+ba+ba+2ba\left| \begin{matrix} a & a + b & a + 2b \\ a + 2b & a & a + b \\ a + b & a + 2b & a \end{matrix} \right| is equal to –

A

9a2 (a + b)

B

9b2 (a + b)

C

a2 (a + b)

D

b2 (a + b)

Answer

9b2 (a + b)

Explanation

Solution

R1 ® R1 + R2 + R3 then C2 ® C2 – C1, C3 ® C3 – C2 D =3

(a + b) × 3b2 = ab2 (a + b)