Question
Question: The value of D= \(\left| \begin{matrix} a & a + b & a + 2b \\ a + 2b & a & a + b \\ a + b & a + 2b ...
The value of
D= aa+2ba+ba+baa+2ba+2ba+ba is equal to –
A
9a2 (a + b)
B
9b2 (a + b)
C
a2 (a + b)
D
b2 (a + b)
Answer
9b2 (a + b)
Explanation
Solution
R1 ® R1 + R2 + R3 then C2 ® C2 – C1, C3 ® C3 – C2 D =3
(a + b) × 3b2 = ab2 (a + b)