Question

The value of current required to deposit 0.972 gm of chromium in 3 hours if the E.C.E. of chromium is 0.00018 gm per coulomb, is

• A. 1 amp
• B. 1.5 amp
• C. 0.5 amp
• D. 2 amp

Answer 1

Answer: (C)

0.5 amp

Answer 2

$i = \frac{m}{Zt} = \frac{0.972}{0.00018 \times 3 \times 3600} = 0.5A$