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Question: The value of \({\cos ^4}\theta - {\sin ^4}\theta \) is equal to: A. \(1 + 2{\sin ^2}\left( {\dfra...

The value of cos4θsin4θ{\cos ^4}\theta - {\sin ^4}\theta is equal to:
A. 1+2sin2(θ2)1 + 2{\sin ^2}\left( {\dfrac{\theta }{2}} \right)
B. 2cos2(θ)12{\cos ^2}\left( \theta \right) - 1
C. 12sin2(θ2)1 - 2{\sin ^2}\left( {\dfrac{\theta }{2}} \right)
D. 2cos2(θ)+12{\cos ^2}\left( \theta \right) + 1

Explanation

Solution

The given question deals with finding the value of trigonometric expression doing basic simplification of trigonometric functions by using some of the simple trigonometric formulae such as cos2x+sin2x=1{\cos ^2}x + {\sin ^2}x = 1 and double angle formula for cosine. Basic algebraic rules and trigonometric identities are to be kept in mind while doing simplification in the given problem. We must know the simplification rules to solve the problem with ease.

Complete step by step answer:
In the given problem, we have to find the value of cos4θsin4θ{\cos ^4}\theta - {\sin ^4}\theta .
So, we have, cos4θsin4θ{\cos ^4}\theta - {\sin ^4}\theta
Using the algebraic identity (a2b2)=(ab)(a+b)\left( {{a^2} - {b^2}} \right) = \left( {a - b} \right)\left( {a + b} \right), we get,
(cos2θ)2(sin2θ)2\Rightarrow {\left( {{{\cos }^2}\theta } \right)^2} - {\left( {{{\sin }^2}\theta } \right)^2}
(cos2θsin2θ)(cos2θ+sin2θ)\Rightarrow \left( {{{\cos }^2}\theta - {{\sin }^2}\theta } \right)\left( {{{\cos }^2}\theta + {{\sin }^2}\theta } \right)
Now, we subtract the trigonometric identity cos2x+sin2x=1{\cos ^2}x + {\sin ^2}x = 1 in the above equation. So, we get,
(cos2θsin2θ)(1)\Rightarrow \left( {{{\cos }^2}\theta - {{\sin }^2}\theta } \right)\left( 1 \right)
Simplifying the expression, we get,
cos2θsin2θ\Rightarrow {\cos ^2}\theta - {\sin ^2}\theta
Now, we know the double angle formula of cosine as cos2x=cos2xsin2x\cos 2x = {\cos ^2}x - {\sin ^2}x. So, we get,
cos(2θ)\Rightarrow \cos \left( {2\theta } \right)
We also know the double angle formula for cosine as cos2x=2cos2x1\cos 2x = 2{\cos ^2}x - 1. Applying this in the expression, we get,
2cos2θ1\Rightarrow 2{\cos ^2}\theta - 1
Therefore, cos4θsin4θ=2cos2θ1{\cos ^4}\theta - {\sin ^4}\theta = 2{\cos ^2}\theta - 1 is the required result.

Hence, option B is the correct answer.

Note: We must have a strong grip over the concepts of trigonometry, related formulae and rules to ace these types of questions. Besides these simple trigonometric formulae, trigonometric identities are also of significant use in such types of questions where we have to simplify trigonometric expressions with help of basic knowledge of algebraic rules and operations. However, questions involving this type of simplification of trigonometric ratios may also have multiple interconvertible answers but we have to mark the most appropriate option among the given choices.